76
General Discussion / Re: Consensus on the list of delegates
« on: February 03, 2015, 08:01:20 am »How does NXT fix this 51% problem ?
Nxt doesn't have delegates. A briber have to pay to almost everyone.
This section allows you to view all posts made by this member. Note that you can only see posts made in areas you currently have access to.
How does NXT fix this 51% problem ?
I could be wrong, but I think a widened block timing would negatively affect the on-blockchain BTS/BitAsset exchange by matching orders less often.
If an honest delegate signs a block that elects one or more new delegates, the newly elected delegates will clearly prefer that fork over the one in which the votes that elected them were ignored.
Really? How is this true in the United States?
...and then just start a new fork.
Basically, it's possible for any election on the planet earth to be "bought" in one way or another. So you're saying that elections are always suspect? That BitShares delegates will care more about a potential small bribe than about their longer term financial interest and fiduciary duty to act in the best interests of BitShares? I certainly don't see this as a solid possibility.
Come-From-Beyond has been explaining for 6 pages, haha. I'll summarize:
- 51 of 101 delegates decide they never want to be fired (via bribery, for example).
- These delegates ignore all blocks from the other 50 delegates. Their chain is longest, so it is accepted. The 50 are powerless.
- The 51 delegates ignore all transactions that vote them out, but they still produce blocks without these transactions.
- In the end, the accepted longest chain never votes them out. They can sell all BTS and maintain control of the chain.
Do I understand correctly?
If I'm an honest delegate, and I see that the longest chain is the hostile chain, I just have to sign my honest vote including block on the end of that formerly hostile chain, and at that point my honest chain is now the longest chain.
In the BitShares network, as long as there are some delegates who continue building on the longest valid chain, and including valid transactions, that group will have an advantage over any group that ignores valid blocks. Even if they start out outnumbered, they can replace delegates by including votes, while hostile groups can only ignore honest delegates.
In the BitShares world, delegates are not government representatives, they are employees of a company. If your scenario happens, what is the actual harm done?
Sure, they'll be excluded from confirmation in the hostile chain, but they'll still be the leaf blocks in that chain after every honest delegate turn. Each such honest leaf block can include votes that replace the hostile delegates and heal the chain.
Are you trying to figure out how to hack the network? Just read the source if so?